Kevin Melanio 12-23-10 skittles Experiment The purposes of this experiment is to hit the books about the exponential function developing and dilapidate. Exponential growth and decay is repeated multiplication. This experiment shows how a two hundred skittles in a home character groundwork be exponential decay as you excite it and sway the 4 sections that is label with an x. Stage shit | add of Skittles | helping of # of skittles | 0 | two hundred | 0.61 | 1 | 122 | 0.63 | 2 | 77 | 0.69 | 3 | 53 | 0.58 | 4 | 31 | 0.52 | 5 | 16 | 0.06 | 6 | 1 | 0 | 7 | 0 | 0 | amount: .38 I got this number by adding the division and dual-lane by the number number of constitute. The intermediate share should be a quarter of 100 portion. The basis that the percent is way stumble we didnt move it correctly and the lines that shared out the plate is not rival to each other. Stage compute | Number of Skittles | Percentage of # of skittles | 0 | 20 | 1.45 | 1 | 29 | 1.62 | 2 | 47 | 1.43 | 3 | 67 | 1.39 | 4 | 93 | 1.39 | 5 | 129 | 1.33 | 6 | 172 | 1.

16 | 7 | two hundred | 0 | Average: 1.39 I got this number by adding the portion and divided by the total number of stage. Uo =200 Uo = 20 n ? 1 n ? 1 Un=Un-1 x .38 Un =Un-1 x 1.39 200 is starting signal line cheer and .38 is the 20 is the starting evaluate and 1.39 is the uniform and thats how many a(prenominal) constant and thats how many I took it out everytime I shook it. I took it out everytime I shook it. Y= 200 x .38^x Y= 20 x 1.38^x 200 is the starting value and x 20 is the starting value and x is the stage is the stage number. .38 is how number. 1.38 is the number of how many candies I took it out.candies I added. Experiment I Experiment II Y=a x b^x Y=a x b^x a=315.2579296 a=22.19081766 b=.4746048684 b=1.40187329...If you necessitate to get a salutary essay, order it on our website:
OrderessayIf you want to get a full information about our service, visit our page: How it works.
No comments:
Post a Comment
Note: Only a member of this blog may post a comment.